Answer:
Heat, Q = 262 kJ
Explanation:
Given that,
Mass of a sample, m = 750 g
Initial temperature, [tex]T_i=95^0\ C[/tex]
Final temperature, [tex]T_f=17^0\ C[/tex]
The specific heat of the sample, [tex]c=4.18\ J/g^0 C[/tex]
We need to find the amount of heat released. The amount of heat released is given by the formula as follows :
[tex]Q=mc\Delta T\\\\Q=750\times 4.48\times (17-95)\\\\Q=-262080\ J\\\\Q=-262\ kJ[/tex]
So, 262 kJ of heat is released by the sample.
