The solution to your problem is as follows:
y = –x² + 6x –11
same objective : f(x) = a(x - h)^2 + k as V(h,k) as vertex
so here:
y = –x² + 6x – 11
y = –(x² - 2*3x + 3^2) – 2
y = - (x - 3)^2 - 2 -----------> h = 3 and k = -2
Therefore, the coordinates of the vertex for the graph is (3,-2).
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
