valiyakathnadim valiyakathnadim
  • 16-12-2020
  • Mathematics
contestada

4radical7-2(2radical7+radical3)+radical12

Respuesta :

erinna erinna
  • 21-12-2020

Given:

[tex]4\sqrt{7}-2(2\sqrt{7}+\sqrt{3})+\sqrt{12}[/tex]

To find:

The value of given expression.

Solution:

We have,

[tex]4\sqrt{7}-2(2\sqrt{7}+\sqrt{3})+\sqrt{12}[/tex]

It can be written as

[tex]=4\sqrt{7}-2(2\sqrt{7}+\sqrt{3})+\sqrt{4\times 3}[/tex]

[tex]=4\sqrt{7}-2(2\sqrt{7}+\sqrt{3})+2\sqrt{3}[/tex]

Using distributive property, we get

[tex]=4\sqrt{7}-2(2\sqrt{7})-2(\sqrt{3})+2\sqrt{3}[/tex]

[tex]=4\sqrt{7}-4\sqrt{7}-2\sqrt{3}+2\sqrt{3}[/tex]

[tex]=0[/tex]

Therefore, the value of given expression is 0.

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