Answer:
x = 1+√83 i/6 and 1-√83 i/6
Step-by-step explanation:
Given the quadratic expression;
3x^2-x+7 =0
Using the general foemula to find x
x = -b±√b²-4ac/2a
From the equation
a = 3, b = -1 and c = 7
Substitute
x = -(-1)±√(1)²-4(3)(7)/2(3)
x = 1±√1-84/6
x = 1±√-83/6
x = 1±√83 i/6
x = 1+√83 i/6 and 1-√83 i/6
