Respuesta :

Answer:

(2x^2 + x-7)/3x+ 3

Step-by-step explanation:

Here, we want to write the following as a single fraction;

2x-1/3 - 2/x + 1

That will be;

(2x-1)(x + 1) -2(3)/3(x+ 1)

= 2x^2+ 2x-x-1-6/3(x + 1)

= (2x^2+x-7)/3(x+1)

= (2x^2 + x-7)/3x+ 3

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