Answer:
138mL are required to make the solution
Explanation:
A solution of 0.270M contains 0.270 moles of solute (NaCl in this case), per liter of solution.
To solve this problem we need to determine the moles of NaCl in 2.18g. With these moles and molarity we can find the volume required to prepare the solution:
Moles NaCl -Molar mass: 58.44g/mol-:
2.18g * (1mol / 58.44g) = 0.0373moles NaCl
Volume of solution:
0.0373moles NaCl * (1L / 0.270moles) = 0.138L
138mL are required to make the solution
