itzashl00
itzashl00 itzashl00
  • 17-12-2020
  • Mathematics
contestada

Can someone help and explain and do the solution pls :(

Can someone help and explain and do the solution pls class=

Respuesta :

umairkazi924
umairkazi924 umairkazi924
  • 17-12-2020

Consider ∆JWZ and ∆JKZ

WZ~KJ (given)

/ WZJ~/ KJZ (given)

JZ~JZ (common)

Therefore,

∆JWZ~∆JKZ by SAS congruence rule.

JW~ZK by CPCT.

Answer Link

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