Answer:
[tex] y = \frac{z^2 - x}{2} [/tex]
Step-by-step explanation:
Given:
[tex] \sqrt{x + 2y} = z [/tex]
Required:
Solve for y (make y the subject of the formula)
SOLUTION:
[tex] \sqrt{x + 2y} = z [/tex]
Square both sides
[tex] (\sqrt{x + 2y})^2 = z^2 [/tex]
[tex] x + 2y = z^2 [/tex]
Subtract both sides by x
[tex] 2y = z^2 - x [/tex]
Divide both sides by 2
[tex] y = \frac{z^2 - x}{2} [/tex]
