Answer:
second option
Step-by-step explanation:
Given
f(x) = [tex]\frac{x+4}{3x-5}[/tex]
The denominator cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the value that x cannot be, that is
3x - 5 = 0 ⇒ 3x = 5 ⇒ x = [tex]\frac{5}{3}[/tex] ← excluded value
Thus domain is
(- ∞, [tex]\frac{5}{3}[/tex] ) u ([tex]\frac{5}{3}[/tex], ∞ )
