Answer:
[tex]A=186.70\ \text{unit}^2[/tex]
Explanation:
Given that,
[tex]\angle QRS = 74^{\circ}\\\\QR = 17\ \text{units}[/tex]
We need to find the area of sector QRS. The formula for the area of a sector is given by :
[tex]A=\dfrac{\theta}{360}\times \pi r^2[/tex]
QR = RS = r = 17 units
So,
[tex]A=\dfrac{74}{360}\times \dfrac{22}{7}\times (17)^2\\\\=186.70\ \text{unit}^2[/tex]
So, the area of sector QRS is [tex]186.70\ \text{unit}^2[/tex]
