Answer:
D. [tex] \frac{22x + 48}{x^2 - 36} [/tex]
Step-by-step explanation:
Given:
[tex] \frac{15}{x - 6} + \frac{7}{x + 6} [/tex]
Required:
Find its equivalent expression
Solution:
Add both fractions
Thus,
[tex] \frac{15}{x - 6} + \frac{7}{x + 6} [/tex]
[tex] \frac{15(x + 6) + 7(x - 6)}{x^2 - 36} [/tex]
[tex] \frac{15x + 90 + 7x - 42}{x^2 - 36} [/tex]
[tex] \frac{15x + 7x + 90 - 42}{x^2 - 36} [/tex]
[tex] \frac{22x + 48}{x^2 - 36} [/tex]
Therefore,
[tex] \frac{15}{x - 6} + \frac{7}{x + 6} = \frac{22x + 48}{x^2 - 36} [/tex]
