Answer:
Rewrite (Lambert form):
[tex]e^{\ln \left(2\right)\left(1-\left(-\frac{u}{\ln \left(2\right)}\right)\right)}\left(-\frac{u}{\ln \left(2\right)}\right)=1[/tex]
Simplify :
[tex]-\frac{e^{\ln \left(2\right)+u}u}{\ln \left(2\right)}=1[/tex]
Solve:
[tex]u=-2\ln \left(2\right),\:u=-1\cdot \ln \left(2\right)[/tex]
Result:
[tex]x=2,\:x=1[/tex]
Hope this helped u :)
If this was too complicated I can edit it for you.
