Respuesta :
Answer:
f'(x) = 2ax + b
Step-by-step explanation:
Differentiate each term using the power rule
[tex]\frac{d}{dx}[/tex] (a[tex]x^{n}[/tex] ) = na[tex]x^{n-1}[/tex]
Given
f(x) = ax² + bx , then
f'(x) = 2a[tex]x^{2-1}[/tex] + b[tex]x^{1-1}[/tex]
= 2ax + b[tex]x^{0}[/tex] ( [tex]x^{0}[/tex] = 1 )
= 2ax + b
The answer above should be correct, I believe it is, but can you please mark me brainlest?
