Answer:
[tex]n = -3/10[/tex]
Step-by-step explanation:
Given the expression [tex]\frac{\sqrt[5]{b} }{\sqrt[]{b} }[/tex]
[tex]\frac{\sqrt[5]{b} }{\sqrt[]{b} } \\= \frac{b^{1/5}}{b^{1/2}} \\= b^{1/5-1/2}\\= b ^{2-5/10}\\= b^{-3/10}\\Compare \ b^n \ with \ b^{-3/10}\\\\n = -3/10[/tex]
