Given that,
Mass of yo-yo, m = 0.5 kg
Radius of the path, r = 2 m
Speed of the object, v = 3 m/s
To find,
The centripetal force acting on the yo-yo.
Solution,
The formula for the centripetal force is given as follows :
[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{0.5\times (3)^2}{2}\\\\F=2.25\ N[/tex]
So, the magnitude of centripetal force acting on the y-yo is 2.25 N.
