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Answer:

[OH⁻] = 0.002 M

Explanation:

The definition of pOH is similar to the definition of pH:

  • pOH = -log[OH⁻]

This means that with a given pOH value, the calculation of [OH⁻] is a matter of algebra:

  • 2.7 = -log[OH⁻]
  • -2.7 = log[OH⁻]

To remove the logarithm we increase 10 by the power of the pOH:

  • [tex]10^{-2.7}[/tex]=[OH⁻]
  • 0.002 M = [OH⁻]

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