Given:
Radius of the circle = 10 in
Central angle of the sector = 45 degrees
To find:
The area of the sector.
Solution:
Area of a sector is
[tex]A=\dfrac{\theta}{360^\circ}\pi r^2[/tex]
Where, [tex]\theta[/tex] is the central angle in degrees.
Putting r=10 and [tex]\theta=45^\circ[/tex], we get
[tex]A=\dfrac{45^\circ}{360^\circ}\pi (10)^2[/tex]
[tex]A=\dfrac{1}{8}\pi (100)[/tex]
[tex]A=12.5\pi[/tex]
Therefore, the area of the sector is 12.5π sq. inches.
