cidw7091 cidw7091

20-02-2021
Mathematics

contestada

Find the equation of a line perpendicular to -3x + 5y = -1 that contains the point (0, -5)

Respuesta :

clarch19 clarch19

21-02-2021

Answer:

y = -5/3x - 5

Step-by-step explanation:

convert -3x + 5y = -1 to slope-intercept form:

5y = 3x - 1

y = 3/5x - 1/5

slope of a line perpendicular to the above equation would be -5/3

y = mx + b

-5 = -5/3(0) + b

b = -5

y = -5/3x - 5

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