Given:
[tex]\sqrt{2}=1.414[/tex]
To find:
The value of [tex]\sqrt{50}+\sqrt{72}[/tex].
Solution:
We have,
[tex]\sqrt{50}+\sqrt{72}[/tex]
It can be rewritten as
[tex]=\sqrt{2\times 25}+\sqrt{2\times 36}[/tex]
[tex]=\sqrt{2}\times \sqrt{25}+\sqrt{2}\times \sqrt{36}[/tex] [tex][\because \sqrt{ab}=\sqrt{a}\sqrt{b}][/tex]
[tex]=5\sqrt{2}+6\sqrt{2}[/tex]
[tex]=11\sqrt{2}[/tex]
Putting [tex]\sqrt{2}=1.414[/tex], we get
[tex]=11(1.414)[/tex]
[tex]=15.554[/tex]
Therefore, the value of given expression is 15.554.
