Respuesta :
Answer:
Step-by-step explanation:
[tex]\frac{3}{x^2-9} +\frac{5}{x+3} \\=\frac{3}{(x+3)(x-3)} +\frac{5}{x+3} \\=\frac{3+5(x-3)}{(x+3)(x-3)} \\=\frac{3+5x-15}{x^2-9} \\=\frac{5x-12}{x^2-9}[/tex]
Answer:
Step-by-step explanation:
[tex]\frac{3}{x^2-9} +\frac{5}{x+3} \\=\frac{3}{(x+3)(x-3)} +\frac{5}{x+3} \\=\frac{3+5(x-3)}{(x+3)(x-3)} \\=\frac{3+5x-15}{x^2-9} \\=\frac{5x-12}{x^2-9}[/tex]
