Respuesta :

tonb

Answer:

[tex]\sum_{i=0}^{15} (3i-1)[/tex]

Step-by-step explanation:

for i=0 you have the first term, 3*0-1 = -1

for i=1 you have the second term, 3*1-1 = 2

...

for i=15 you have the last term, 3*15-1 = 44

Otras preguntas