Answer:
Height of the tree is 20.25 m.
Step-by-step explanation:
Length of building AB = 54 m
Length of tree DE = 9 m
Shadow casted by the building (BC) = 24 m
Shadow casted by the tree (CE) = 9 m
Since, ΔABC ~ ΔDEC
By the property of similar triangles, corresponding sides of the similar triangles will be proportional.
[tex]\frac{AB}{DE}=\frac{BC}{EC}[/tex]
[tex]\frac{54}{h}=\frac{24}{9}[/tex]
h = [tex]\frac{54\times 9}{24}[/tex]
h = 20.25 m
Therefore, height of the tree is 20.25 m.
