Answer:
3 and 5
Step-by-step explanation:
Let the two consecutive odd integers be x and x + 2.
Now,
The given statement is
[tex]x^2 + 3 \times (x+2)=24\\x^2 + 3x+6-24 = 0 \\x^2 + 3x-18 = 0\\x^2+6x-3x-18=0\\x(x+6)-3(x+6)=0\\(x-3)(x+6)=0\\x=3,-6[/tex]
Taking x=3.
Hence, two consecutive odd integers are 3 and 5.
