Respuesta :

syed514
they appear to be using the (2x) as the variable;
so,
e^(t) + t^2 ;
now fill in the interval [0,2x]
 e^(2x) + (2x)^2 -e^(0)
 D{t} [e(2x) +4x^2 - 1]
 2e^(2x) + 8x