Answer:
H2SO4 + 2NAOH➡NA2SO4+2H2O
H2SO4 = 1*2 +32+16*3= 98g
NAOH = (11+16+1)=28
Explanation:
To calculate the number of Mole = Mole *Molar Mass
To calculate for gram = Mole/ Molar Mass
20.5g NaoH/1 * 1 mole NaOH/28g NaoH = 0.73M NaoH
0.73M NaoH /1 * 1 M H2SO4 /2M NaoH = 0.37M H2SO4
0.37 M H2SO4 /1 * 98g H2SO4 /1M H2SO4 = 0.00367g H2SO4
:- 0.00367g of Sulphuric Acid will be needed to complete the reaction.
