Answer:
2.0 g CaCO₃
Explanation:
We are given molarity and volume, so we can find moles since molarity is moles of solute divided by volume of solution in liters. We can then convert from moles to grams using the molar mass of CaCO₃.
2 L x 0.010 mol/1 L x 100.0869 g/1 mol = 2.0 g CaCO₃ (two significant figures)
