Answer:
The acceleration of the runner is 0.25 m/s²
Explanation:
Given;
distance covered by the runner, d = 200 m
time of motion, t = 10 s
initial velocity of the runner, u = 0 (he started standing still)
final velocity of the runner, v = 36 km/h = 10 m/s
Therefore, to achieve the final speed of the runner, his acceleration is calculated as follows;
v² = u² + 2as
10² = 0 + (2 x 200)a
100 = 400a
a = 100/400
a = 0.25 m/s²
The acceleration of the runner is 0.25 m/s²
