Answer:
the numbers are 15, 18, 21
Step-by-step explanation:
let the 3 consecutive multiples of 3 be:
3x, 3(x+1), 3(x+2)
(2/3)(3x + 3(x+1)) =3(x+2)+1
(2 /3)(6x+ 3) = 3x+6+1
2(2x+1) = 3x + 7
4x + 2 = 3x + 7
x = 5
so:
3x = 15
3(x+1) = 18
3(x+2) = 21
the numbers are 15, 18, 21
