Answer:
E = 4000 N/C
Explanation:
Given the following data;
Force = 0.080 N.
Charge, q = 20 microcoulomb = 20 * 10^-6 = 2 * 10^-5 Coulombs
To find the electric field strength;
Mathematically, the electric field strength is given by the formula;
Electric field strength = force/charge
Substituting into the formula, we have;
E = 0.080/0.00002
E = 4000 N/C
