Answer:
B. 1
Step-by-step explanation:
[tex]\lim_{x \to -3} \sqrt{x^2 - 8}[/tex]
Here we have
[tex]\lim_{x \to -3} f(x)=f(x)[/tex]
Therefore
[tex]\lim_{x \to -3} \sqrt{x^2 - 8} = \lim_{x \to -3} \sqrt{(-3)^2 - 8} = \lim_{x \to -3} \sqrt{9 - 8} = \lim_{x \to -3} \sqrt{1}[/tex]
[tex]\lim_{x \to -3} \sqrt{1}= \lim_{x \to -3} 1 = 1[/tex]
