Answer: [tex](-3,18),\ (3,6)[/tex]
Step-by-step explanation:
Given
Functions are [tex]x^2-2x+3\ \text{and}\ -2x+12[/tex]
Equate them to solve
[tex]x^2-2x+3=-2x+12\\\Rightarrow x^2=9\\\Rightarrow x=\pm 3\\\therefore y=6,18\\\text{Ordered pairs are}\\(-3,18),\quad (3,6)[/tex]
