Respuesta :
Answer:
[tex]RFM \: of \: ammonia = 17 \\ 6.02 \times {10}^{23} \: molecules \: weigh \: 17 \: g \\ 3.80 \times {10}^{24} \: will \: weigh \: ( \frac{3.80 \times {10}^{24} }{6.02 \times {10}^{23} } \times 17) \: g \\ = 107.3 \: g[/tex]
Answer:
[tex]RFM \: of \: ammonia = 17 \\ 6.02 \times {10}^{23} \: molecules \: weigh \: 17 \: g \\ 3.80 \times {10}^{24} \: will \: weigh \: ( \frac{3.80 \times {10}^{24} }{6.02 \times {10}^{23} } \times 17) \: g \\ = 107.3 \: g[/tex]
