Answer:
[tex]x\le \:-1[/tex]
Step-by-step explanation:
[tex]3\left(x-1\right)\le \frac{1}{2}\left(x+1\right)-6[/tex]
[tex]3x-3\le \:-\frac{11}{2}+\frac{1}{2}x[/tex]
[tex]3x\le \:-\frac{5}{2}+\frac{1}{2}x\\[/tex]
[tex]\frac{5}{2}x\le \:-\frac{5}{2}[/tex]
[tex]5x\le \:-5[/tex]
[tex]x\le \:-1[/tex]
x = -1
3(-2) ≤ ½(0) - 6
-6 ≤ 0 - 6
-6 ≤ -6
This is true.
x = -2
3(-3) ≤ ½(-1) - 6
-9 ≤ -½ - 6
-9 ≤ [tex]-\frac{13}{2}[/tex]
This is also true.
Therefore, x ≤ -1.
