Answer:
Step-by-step explanation:
if two chords of a circle are at equal distance from the center then they are equal.
OP=OQ
AB=CD
AB=2PB=2(3x-17)=6x-34
because perpendicular from the center on a chord bisects the chord.
6x-34=15-x
6x+x=15+34
7x=49
x=7
AB=6×7-34=42-34=8
PB=3×7-17=21-17=4
Radius of circle=√(OP²+PB²)=√(3²+4²)=√(9+16)=√(25)=5
