Respuesta :

sqdancefan

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Answer:

  -2k·ln(7)

Step-by-step explanation:

49 is a perfect square, so the argument of the log function can be written as ...

  1/46^k = 1/(7^2)^k = 1/7^(2k) = 7^(-2k)

Then the log of it is ...

  ln(7^(-2k)) = -2k·ln(7)