If 101 is given in base b, then in base 10 you have
[tex]101_b = 1\times b^2 + 0\times b^1 + 1\times b^0 = b^2 + 1[/tex]
For instance, if b = 2, then
101₂ = 2² + 1 = 5₁₀
If b = 3, then
101₃ = 3² + 1 = 9₁₀
If b = 4, then
101₄ = 4² + 1 = 17₁₀
The answer depends entirely on the base of the given number.
