Answer:
Solution:
The vector diagram for various velocities is shown.Vector AC gives velocity of aeroplane relative to quiet air.Vector CB gives velocity of wind(air) relative to ground.Vector AB gives velocity of plane relative to ground.Using law of sines for triangle,
sin30
0
150
=
sinθ
20
.
Therefore,sin(θ)=
300
20
=
15
1
. Then,
Theta=sin
−1
15
1
=3.8
0
.
Angle NAC=33.8
0
.The pilot should head the plane in the direction 33.8
0
east of north
Step-by-step explanation:
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