Answer:
[tex] \dashleftarrow _{40 \: km}↑ _{160 \: km}[/tex]
• from pythogras theorem:
[tex]{ \tt{displacement = \sqrt{ { (- 40})^{2} + {160}^{2} } }} \\ \\ = { \tt{ \sqrt{27200} }} \\ \\ ={ \tt{165 \: km}}[/tex]
Direction: tan(A) = 160/40
A = tan^-1 (160/40)
A =76°
Answer: Displacement is 165 km in N076°W
