Respuesta :

kamilmatematik100504

Answer:  -√3

Step-by-step explanation:

  • The tangent is positive in the II and III quarters
  • A is negative in the I and IV quarters
  • [tex]\displaystyle \sf \large \boldsymbol {} \boxed{tg(x-y)=\frac{tgx-tgy}{1+tgx\cdot tgy} }\\\\\ \\ tg(180-60)= \frac{tg180-tg60}{1+tg180} =\frac{0-tg60}{1-0}=-tg60=-\sqrt{3} \\\\or\\\\tg120=tg(180-60)= -tg60= \boxed{-\sqrt3}[/tex]