Answer:
(y-3)²= -32x
Step-by-step explanation:
1) the required equation has a form: (y-y₀)²=-2p(x-x₀), where (x₀;y₀) - vertex (0;3), p - parameter of the given parabola;
x₀=0; y₀=3.
2) according to the conditiion F(-8;3)=F(x₀+p/2; y₀), it means (x₀+p/2; y₀)=(p/2;3), then p/2= -8; ⇒ p= -16.
3) finally, p= -16; x₀=0; y₀=3, then it is possible to make up the required equation:
(y-3)²= -32x.
PS/ if it is possible check the suggested solution in other sources.
