Based on the information given, it can be deduced that the value of the 15th term is 50.
a + 8d = 32 ..... i
a + 4d = 20 ...... ii
Subtract ii from i
4d = 12
d = 12/4
d = 3
Therefore, a will be:
a + 4d = 20
a + 4(3) = 20
a + 12 = 20
a = 20 - 12 = 8
Therefore, the 15th term will be:
= a + 14d
= 8 + 14(3)
= 8 + 42
= 50
The 15th term is 50.
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