Answer:
A
Step-by-step explanation:
Given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = - [tex]\frac{b}{2a}[/tex]
y = 2x² - 4x + 5 ← is in standard form
with a = 2 and b = - 4 , then
[tex]x_{vertex}[/tex] = - [tex]\frac{-4}{4}[/tex] = 1
Substitute x = 1 into the equation for corresponding value of y
y = 2(1)² - 4(1) + 5 = 2 - 4 + 5 = 3
vertex = (1, 3 ) → A
