contestada

g A population of geckos is in a Hardy Weinberg equilibrium state and has 50 individuals of genotype AA, 100 of genotype Aa, and 100 of genotype aa. What are the predicted allele frequencies of A (p) and a (q)

Respuesta :

luisvaschetto

The predicted allele frequencies of A (p) and a (q) are A= 0.4 and a = 0.6. The Hardy–Weinberg principle states that allele frequencies in a population will remain constant across generations in absence of evolutionary forces.

The Hardy–Weinberg principle is used in population genetics to estimate allele and genotype frequencies in a given population.

According to this model, allele and genotype frequencies in a population will remain constant across generations in absence of different evolutionary forces.

In this case, it is possible to easily calculate the allele frequencies from the data.

Genotypes:

  • AA = 50
  • Aa = 100
  • aa = 100

Allele and genotype frequencies:

  • Allele frequency A (p) = [(50 x 2) + 100]/500 = 0.4 >> AA (q2) = 0.16
  • Allele frequency a (q) = [(100 x 2) + 100]/500 = 0.6 >> aa (p2) = 0.36
  • Frecuency heterozygotes Aa >> 2 x p x q  >> 2 x 0.4 x 0.6 = 0.48

Learn more in:

https://brainly.com/question/8667324

Otras preguntas