Answer:
B 6[tex]\sqrt{y}[/tex]
Step-by-step explanation:
6y 1/2
[tex]6\sqrt{2y}[/tex]
[tex]\frac{12y}{\sqrt{2y} }\\\\\frac{12y}{\sqrt{2y} }\cdot\frac{\sqrt{2y} }{\sqrt{2y} }\\\\\frac{12y(\sqrt{2y}) }{2y}\\\\6\sqrt{2y}[/tex]
