Respuesta :

Step-by-step explanation:

Let,

Cost of one trouser = $x

Cost of one coat = $y

In case 1

x + 3y = 52 (1)

In case 2

4x + 4y = 72

x + y = 18 (2)

On subtracting

x + 3y - (x + y) = 52 - 18

x + 3y - x - y = 52 - 18

2y = 34

y = 34/2

y = $17

From 2

x + y = 18

x + 17 = 18

x = 18 - 17

x = $1

Now,

Cost of 6 trouser and 6 coats

6x + 6y

6(x + y)

6(1 + 17)

6(18)

$108

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