ryanmalhotra
ryanmalhotra ryanmalhotra
  • 20-12-2021
  • Mathematics
contestada

Let f(x) = 2(x − 1)² + 3 and h(x) = -f(x+3) - 1

Write h in terms of x

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Аноним Аноним
  • 21-12-2021

f(x+3)

[tex]\\ \sf\Rrightarrow 2(x+3-1)^2+3[/tex]

[tex]\\ \sf\Rrightarrow 2(x+2)^2+3[/tex]

[tex]\\ \sf\Rrightarrow 2(x^2+4x+4)+3[/tex]

[tex]\\ \sf\Rrightarrow 4x^2+8x+8+3[/tex]

[tex]\\ \sf\Rrightarrow 4x^2+8x+11[/tex]

Now

[tex]\\ \sf\Rrightarrow h(x)[/tex]

[tex]\\ \sf\Rrightarrow -f(x+3)-1[/tex]

[tex]\\ \sf\Rrightarrow -4x^2-8x-11-1[/tex]

[tex]\\ \sf\Rrightarrow -4x^2-8x-12[/tex]

[tex]\\ \sf\Rrightarrow 4(-x^2-2x-3)[/tex]

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