Answer:
3(cos(π/4) +i·sin(π/4))
Step-by-step explanation:
The relevant relation is ...
x +yi = r(cos(θ) +i·sin(θ))
where ...
r = √(x² +y²)
θ = arctan(y/x) . . . . with attention to quadrant
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Using the given values of x and y, you have ...
r = √((3√2/2)² +(3√2/2)²) = √(9/2 +9/2) = 3
θ = arctan((3√2/2)/(3√2/2)) = arctan(1) = π/4 . . . . a first-quadrant angle
Your polar-form equivalent is ...
3(cos(π/4) +i·sin(π/4))
