Answer:
The missing side has a length equal to [tex]15\sqrt{3}[/tex]
Step-by-step explanation:
We need to find the length of the missing side on the right triangle. We were given the length of the hypotenuse, and the opposite cathetus, therefore we can use the sine relation. This is done below:
[tex]sin60=\frac{x}{30}\\\frac{\sqrt{3}}{2}=\frac{x}{30}\\x=15\sqrt{3}[/tex]
