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  • 20-01-2022
  • Chemistry
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S8 + 12O2 = ​​​8SO3

​If it takes 36.72 grams of O2 to begin the reaction, how many grams of SO3 will be formed?

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Аноним Аноним
  • 20-01-2022
  • 12mol of O_2 forms 8 moles of SO_3
  • 3mol of O_2 forms 2mol of SO_3
  • 1mol of O_2 forms 0.6mol of SO_3

Lets calculate moles of O_2

[tex]\\ \sf\longmapsto \dfrac{Given\:mass}{Molar\:mass}[/tex]

[tex]\\ \sf\longmapsto \dfrac{36.72}{32}[/tex]

[tex]\\ \sf\longmapsto 1.14mol[/tex]

moles of SO_3

  • 1.14(0.6)=0.684mols

Mass of SO_3

[tex]\\ \sf\longmapsto 0.683(80)=54.6g[/tex]

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