Write the formula
Lead (Il) acetate
Pb(C2H302)2
2) Find the molar mass of every element
Pb: 207.2 g/mol
C: 12.011 g/mol
H: 1.008 g/mol
O: 15.999 g/mol
3) Multiply each mass by the
corresponding subscript.
Pb: 207.2 g/mol* 1
207.2 g/mol
C: 12.011 g/mol* 4 =
48.044 g/mol
H: 1.008 g/mol* 6 =
6.048 g/mol
O: 15.999 g/mol* 4 =
63.996 g/mol
There are 0.4765 mol of Pb(C2H3O2)2 in 155 g
